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Let's play Bocce (Posted on 2021-06-02) Difficulty: 2 of 5
In the game of Bocce, two opponents each throw four balls of their color, trying to get closest to a small neutral ball called the pallino. The player with the ball closest to the pallino scores however many of their balls are closer than the closest of their opponent.

Consider two opponents with zero skill. Although their balls all remain in play, the distances of the eight balls to the pallino are completely random.

Find the winning player's expected number of points.

Extension.
The sport of curling, while played on ice, uses similar scoring except that each team curls eight stones towards a fixed point called the 'tee.' After curling all the stones, the team with the stone closest to the 'tee' scores however many of their stones are closer than the closest of their opponent. Only stones in the 'house' can score.

Again, imagine the teams have zero skill but all of the 16 stones ending up in the house but at a random position.

Find the winning team's expected number of points.

No Solution Yet Submitted by Jer    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution solution | Comment 1 of 6
for n=1:10
   trials=repmat('ab',n);
   trials=trials(1,:);
   way=uniqueperms(trials);
   ct=0;
   for i=1:size(way,1)
      tr=way(i,:);
      for j=2:n+1
         if tr(j)~=tr(1)
            break 
         end
      end
      ct=ct+j-1;
   end
   ev=sym(ct/size(way,1));

   fprintf('%2d %6s %8d %8d %13f\n',n,ev,ct,i, double(ev))
end

The function uniqueperms is available online in the MATLAB file exchange.

The table produced by the above program shows for n = the number of balls or stones rolled or shot by each person or team, the expected score for the winning team as a rational number, the numerator and denominator of the unreduced fraction and the expected value as a decomal.

 n  expected     unreduced        decimal
     score      num     den
 1      1        2        2      1.000000
 2    4/3        8        6      1.333333
 3    3/2       30       20      1.500000
 4    8/5      112       70      1.600000
 5    5/3      420      252      1.666667
 6   12/7     1584      924      1.714286
 7    7/4     6006     3432      1.750000
 8   16/9    22880    12870      1.777778
 9    9/5    87516    48620      1.800000
10  20/11   335920   184756      1.818182

For the case of Bocce (n=4), there are 70 unique orders of distance, in which the total of points scored for all 70 is 112, giving an average score of 8/5.

For curling (n=8) it would be 22,880 points scored over the total of 12,870 possible orders, for an average of 16/9 points scored.

As the number of object pitched per team increases, the expected points approaches 2.

  Posted by Charlie on 2021-06-02 10:32:07
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