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A different angle (Posted on 2003-10-10) Difficulty: 3 of 5
Look at this shape:

Assume AB = AF = FE = ED and BC = CD, and all the angles in the shape are 90 degrees.

Let A be the area of this shape (in cm^2), and P -- the perimeter of this shape (in cm).

If A - P is 60, what is the length of line AC?

See The Solution Submitted by Lewis    
Rating: 1.9167 (12 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
is this a bit too easy? | Comment 21 of 23 |

Let AB = n, then BC = 2n

Area = (2n)^2 - n^2 = 3n^2

P = 4(n) + 2 (2n) = 8n

A-P = 3n^2 - 8n = 60

3n^2 - 8n - 60 = 0

(n - 6) (3n + 10) = 0

n = 6 or - 3/10 (rejected)

AC^2 = 6(6) + (12)(12)

AC = 13.42

well

Edited on October 15, 2005, 4:19 am

Edited on October 15, 2005, 4:20 am
  Posted by Terence on 2005-10-15 04:18:32

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