Look at this shape:

Assume AB = AF = FE = ED and BC = CD, and all the angles in the shape are 90 degrees.

Let **A** be the area of this shape (in cm^2), and **P** -- the perimeter of this shape (in cm).

If **A - P** is **60**, what is the length of line AC?

(In reply to

answer by K Sengupta)

Let the sides BC =CD= y(say)

Then, A = y^2 -(y^2/4) = 3*(y^/4)

and, P = 2y+2y = 4y

Thus, by conditions of the problem:

3*(y^2/4) - 4y = 60

Or, 3*y^2 - 16y -240 = 0

Or, (y-12)(3y+ 20) = 0

Or, y = 12, ignoring the negative root which is inadmissible.

Consequently, AC = V(y^2 + (y^2)/4)

= V(6^2+12^2)

= 13.4164 units (approx.)

*Edited on ***September 25, 2007, 1:38 pm**