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Product of odd primes with distinct digits (Posted on 2021-07-23) Difficulty: 2 of 5
(1): Consider the set of the smallest 6 odd primes: {3,5,7,11,13,17}.
What is the largest multiple of this product which has distinct digits ?

(2) What is the maximum number of digits a square-free integer (whether even or odd) can have if its digits are all distinct?

(3) What is the largest odd square-free integer with distinct digits having exactly n prime factors for n = 1,2,3,4,5? You can extend this to larger numbers of factors if you wish.

Note: a square-free integer is one whose prime factorization has exactly one factor for each prime that appears in it.

  Submitted by Larry    
Rating: 5.0000 (2 votes)
Solution: (Hide)
Part (1): 876290415

Part (2): Nine digits. It cannot have 10 digits since such a pandigital has a sum of digits of 45 and is thus a multiple of 9. So '3' would be a factor twice. It might have 9 digits, but the s.o.d. will still have to be NOT a multiple of 9, so the "missing" digit cannot be 0 or 9.

Part (3):
Limiting the results to odd square-free integers.
n .. product .... factors
1 987654103 [987654103]
2 987654301 [2029, 486769]
3 987654201 [3, 23, 14313829]
4 987652403 [41, 53, 61, 7451]
5 987652043 [7, 17, 29, 137, 2089]

Comments: ( You must be logged in to post comments.)
  Subject Author Date
coursework help ukMitchell Mercer2021-10-26 08:41:55
re: Brian and Charlie: note a few detailsCharlie2021-07-27 21:56:47
Hints/TipsBrian and Charlie: note a few detailsLarry2021-07-25 09:44:57
Solutioncomputer solutionCharlie2021-07-23 14:16:24
SolutionQuestion 2 and 3 answers.Brian Smith2021-07-23 12:16:36
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