Determine the present ages of each of the three siblings Toby, Julie and Melanie from the following clues:

- 10 years from now Toby will be twice as old as Julie was when Melanie was 9 times as old as Toby.
- 8 years ago, Melanie was half as old as Julie will be when Julie is 1 year older than Toby will be at the time when Melanie will be 5 times as old as Toby will be 2 years from now.
- When Toby was 1 year old, Melanie was 3 years older than Toby will be when Julie is 3 times as old as Melanie was 6 years before the time when Julie was half as old as Toby will be when Melanie will be 10 years older than Melanie was when Julie was one-third as old as Toby will be when Melanie will be 3 times as old as she was when Julie was born.

"when Melanie was 9 times as old as Toby"

I took "when" here to mean: the same year in which M was 9 times as old as T, not the year in which M was 9 times as old as T is now.

So I wrote:

M-P = 9(T-P)

where P is the number of years ago this 9-times age difference occurred.

I think perhaps Charlie interprets the statement differently, using T's current age: M-P = 9T

But this only means that we are getting solutions for different problems.

I have also gone back and fixed one error I found in my first post,

which changes the answer, but doesn't yet get a reasonable result.

Currently I have negative P and F values (negative years) and a negative age for T, all of which are nonsensical. - Checking further...

*Edited on ***January 9, 2022, 11:57 am**