perplexus.info :: Geometry : Closest approaches

Closest approaches (Posted on 2022-01-14)

ABCD is a unit square with movable point E on side CD.
P₁ is on the same side of Line AE as D and P₂ is on the other side such that AEP₁ and AEP₂ are equilateral triangles.

(A) Find the smallest possible distance P₁D.

(B) Find the distance CE that minimizes P₂B.

No Solution Yet Submitted by Jer

Rating: 3.0000 (1 votes)

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Puzzle Answer

Comment 3 of 3 |

(A) The required smallest distance P_1D is 0.5

(B) The required distance CE that minimizes P_2B is 0.5

Posted by K Sengupta on 2022-07-07 00:42:37

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