Three different squares are chosen randomly on a chessboard.
What is the probability that they lie in the same diagonal?
(In reply to Simple solution (no program used)
Penny, you wrote:
"So the odds that all three are on the same diagonal, are:
(28/64)*(7/63)*(7/62) + (20/64)*(9/63)*(9/62) + (12/64)*(11/63)*(11/62) + (4/64)*(13/63)*(13/62)
I don't understand how you came up with these odds, but they seem incorrect.