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 Chessboard (Posted on 2004-01-14)
Three different squares are chosen randomly on a chessboard.

What is the probability that they lie in the same diagonal?

 No Solution Yet Submitted by Ravi Raja Rating: 3.5000 (8 votes)

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 re: Corrected solution | Comment 6 of 20 |
(In reply to Corrected solution by Penny)

Penny, you wrote:
"So the true odds are:

(4/64)*(7/63)
+ (8/64)*(6/63)
+ (8/64)*(2/63)*(1/62) + (8/64)*(5/63)*(4/62)
+ (8/64)*(3/63)*(2/62) + (8/64)*(4/63)*(3/62)
+ (4/64)*(2/63)*(1/62) + (4/64)*(7/63)*(6/62)
+ (8/64)*(3/63)*(2/62) + (8/64)*(6/63)*(5/62)
+ (8/64)*(4/63)*(3/62) + (8/64)*(5/63)*(4/62)
+ (4/64)*(4/63)*(3/62) + (4/64)*(7/63)*(6/62)
+ (8/64)*(5/63)*(4/62) + (8/64)*(6/63)*(5/62)
+ (4/64)*(6/63)*(5/62) + (4/64)*(7/63)*(6/62)

= 0.0076804916"

I don't understand how you are coming up with these probabilities, but they appear incorrect.
______________________

BTW, this Al-Gore-ithm thing... did this occur before or after Al invented the internet?
 Posted by SilverKnight on 2004-01-14 19:05:18

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