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Last Digit (Posted on 2004-01-23) Difficulty: 3 of 5
Find the last digit of summation of the series:
(1)^99 + (2)^99 + (3)^99 + (4)^99 + + (98)^99 + (99)^99

See The Solution Submitted by Ravi Raja    
Rating: 2.4000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts re: last digit | Comment 14 of 19 |
(In reply to last digit by Purna)

How come you get from last_digit((2^100)/2 to last_digit(2/2)?? The last digit of 2^100 is 6, so the result should be 3, not 1; the whole reasoning is wrong.
  Posted by e.g. on 2004-01-27 09:16:50

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