Find the smallest number such that if its rightmost digit is placed at its left end, the new number so formed is precisely 50% larger than the original number.
(In reply to
Conclusion of the Ramblings by Victor Zapana)
The problem doesn't actually specify that the answer must be integral does it? Why wouldn't 2.85714 work? (Or .285714 if the preceeding "0" isn't required?) For that matter (and I'm just working from Victor's previous reasoning) there may a number 1.********** that would work and be smaller, but have more "digits" than 6.

Posted by stan
on 20040126 09:54:15 