Find sum of digits of:(1999)^1999.
[The final answer should be a single digit number, for example, (2)^16 = 65536 and the sum of its digits will be given by (6 + 5 + 5 + 3 + 6 = 25, which again will be reduced to 2 + 5 = 7].

We have a rule that the digit sum of a given number is equal to product of the digit sums of the individual factors of the given number.

The digit sum of 19999 is equal to 1.
So sum of the digits of given number is 1.

Posted by Purna on 2004-01-29 03:39:07