All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Diagonals Of A Polygon (Posted on 2004-01-31) Difficulty: 2 of 5
A polygon has 1325 diagonals. How many vertices does it have?

No Solution Yet Submitted by Ravi Raja    
Rating: 2.4167 (12 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution My Solution | Comment 10 of 16 |
The formula for number of diagonals in a polygon is
n(n-3)/2 where n is the number of sides.
Since here, we are given the number of diagonals,
n*n - 3n = 2650
n*n - 3n - 2650 = 0,
we get n as 53. Hence the number of sides is 53, and since the number of sides = number of vertices, the number of vertices is 53.

  Posted by shawn on 2004-02-15 22:19:54
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information