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The Cannibals (Posted on 2004-02-04) Difficulty: 1 of 5
The Cannibals of an Island have the habit of eating each other.
One evening, the cannibals threw a dinner party. Six cannibals turned up and they decided to eat each other in turn. So someone was selected for everyone to eat (except the victim!), and when he had been eaten, someone else was selected, and so on.
If it took one cannibal two hours on his own to devour one person, how long was it before just one consumer remained?

  Submitted by Ravi Raja    
Rating: 1.2857 (7 votes)
Solution: (Hide)
It took 4 hours 34 minutes for one cannibal to remain. It took 5 cannibals, 2/5 hours to eat the first victim, four cannibals 2/4 hours to devour the second, three cannibals 2/3 hours for the third, two cannibals 2/2 hours for the fourth and one cannibal 2/1 hours for the fifth.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
selection processjamie2005-03-19 02:31:21
SolutionSolutionCoda2004-03-01 16:15:18
Potential SolutionSeth2004-02-08 16:10:23
Solutionsolutionethan2004-02-05 18:57:45
possible solution: semantic issuestim2004-02-05 11:04:43
SolutionGross GuessworkStu2004-02-05 04:27:34
A tough mealP C2004-02-04 12:56:10
re: Stomach ContentsPenny2004-02-04 12:32:01
Stomach ContentsJils2004-02-04 11:29:44
re: Solution (...what am I overlooking this time?)Ady TZIDON2004-02-04 09:47:33
SolutionSolution (...what am I overlooking this time?)Penny2004-02-04 09:41:16
tasteless solutionAdy TZIDON2004-02-04 09:38:25
SolutionSolution (add on)Popstar Dave2004-02-04 09:37:21
SolutionSolutionPopstar Dave2004-02-04 09:20:28
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