All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 The Cannibals (Posted on 2004-02-04)
The Cannibals of an Island have the habit of eating each other.
One evening, the cannibals threw a dinner party. Six cannibals turned up and they decided to eat each other in turn. So someone was selected for everyone to eat (except the victim!), and when he had been eaten, someone else was selected, and so on.
If it took one cannibal two hours on his own to devour one person, how long was it before just one consumer remained?

 Submitted by Ravi Raja Rating: 1.2857 (7 votes) Solution: (Hide) It took 4 hours 34 minutes for one cannibal to remain. It took 5 cannibals, 2/5 hours to eat the first victim, four cannibals 2/4 hours to devour the second, three cannibals 2/3 hours for the third, two cannibals 2/2 hours for the fourth and one cannibal 2/1 hours for the fifth.

Comments: ( You must be logged in to post comments.)
 Subject Author Date selection process jamie 2005-03-19 02:31:21 Solution Coda 2004-03-01 16:15:18 Potential Solution Seth 2004-02-08 16:10:23 solution ethan 2004-02-05 18:57:45 possible solution: semantic issues tim 2004-02-05 11:04:43 Gross Guesswork Stu 2004-02-05 04:27:34 A tough meal P C 2004-02-04 12:56:10 re: Stomach Contents Penny 2004-02-04 12:32:01 Stomach Contents Jils 2004-02-04 11:29:44 re: Solution (...what am I overlooking this time?) Ady TZIDON 2004-02-04 09:47:33 Solution (...what am I overlooking this time?) Penny 2004-02-04 09:41:16 tasteless solution Ady TZIDON 2004-02-04 09:38:25 Solution (add on) Popstar Dave 2004-02-04 09:37:21 Solution Popstar Dave 2004-02-04 09:20:28

 Search: Search body:
Forums (3)