All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 The Amazing Stamp (Posted on 2003-12-01)
You have an ink stamp that is so amazingly precise that, when inked and pressed down on the plane, it makes every circle whose radius is an irrational number (centered at the center of the stamp) black.

Is it possible to use the stamp three times and make every point in the plane black?

If it is possible, where would you center the three stamps?

 See The Solution Submitted by DJ Rating: 4.4545 (11 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 Solution | Comment 20 of 45 |
Let x be any positive number such that x^2 is irrational.
Let AC be any line segment on the plane with length 2x.
Let B be the midpoint of AC.
Let P be any point in the plane.
Let u be the length of PA.
Let v be the length of PB
Let w be the length of PC.
Let T be the measure of angle ABP.
```          P

/|\_

/ \  \_

u/   \   \__

/    |v    w\_

/      \       \_

/      T \        \

---A---------B---------C---

x          x

```

By the law of cosines:
u^2 = v^2 + x^2 - 2vx*cos(T)
w^2 = v^2 + x^2 - 2vx*cos(pi-T)

Since cos(pi-x) = -cos(x), the second equation can be written as
w^2 = v^2 + x^2 + 2vx*cos(T)

Adding the two equations together yeilds
u^2 + w^2 = 2v^2 + 2x^2

If we assume u, v, and w are all rational, then a contradiction is formed because if both u and w are rational then v^2 = (u^2 + w^2 - 2x^2)/2 is irrational which means v must be irrational.

So points A, B, and C are three points which allow the stamp to cover the entire plane.
Edited on December 9, 2003, 10:08 am
 Posted by Brian Smith on 2003-12-03 11:22:29

 Search: Search body:
Forums (0)