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e pluribus unum (Posted on 2003-12-08) Difficulty: 3 of 5
Below are three groups of three numbers each. Combine the numbers in each group using the standard binary operations (addition, subtraction, multiplication, division, and exponentiation) so that each group yields the same number (there is one unique solution).
  1. 1, 6, 11
  2. 13, 20, 33
  3. 20, 33, 40
For example, given:
15, 19, 24          11, 30, 36          20, 22, 36
you could make:
24(19-15)=6       (30+36)11=6         20+22-36=6

See The Solution Submitted by DJ    
Rating: 3.8462 (13 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Please don't: | Comment 6 of 11 |
Post problems in the chat. Even easy ones. This means all problems.

Please don't insult others' problems

Finally, I would prefer if you kept your illegal events to yourself, as they don't add any color to the site, and stop mentioning your boyfriend. Random fact: People who lie assert a fact much more than people who tell the truth.
  Posted by Gamer on 2003-12-08 22:04:09
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