perplexus.info :: Just Math : e pluribus unum

e pluribus unum (Posted on 2003-12-08)

Below are three groups of three numbers each. Combine the numbers in each group using the standard binary operations (addition, subtraction, multiplication, division, and exponentiation) so that each group yields the same number (there is one unique solution).

1, 6, 11
13, 20, 33
20, 33, 40

For example, given:
15, 19, 24          11, 30, 36          20, 22, 36
you could make:
24÷(19-15)=6       (30+36)÷11=6         20+22-36=6

Submitted by DJ

Rating: 3.8462 (13 votes)

Solution: (Hide)

1 × 6 × 11 = 66 13 + 20 + 33 = 66 33 × 40 ÷ 20 = 66

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
More than one solution...	Dej Mar	2012-09-23 06:42:17
Solution	Praneeth Yalavarthi	2007-07-17 12:59:13
Solution	K Sengupta	2007-03-16 10:56:49
agreeing about solution	Emily	2005-08-26 21:39:19
Don't start that again	Minion123	2003-12-09 01:29:00
Please don't:	Gamer	2003-12-08 22:04:09
a wild stab	ken	2003-12-08 21:56:15
re: This one was really hard....	Victor Zapana	2003-12-08 20:58:51
This one was really hard....	Penny	2003-12-08 18:54:31
Solution	ethan	2003-12-08 16:38:47
Solution (No computer program used)	Penny	2003-12-08 16:22:14

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