In a game show, there is a game in which you have to order the value of three prizes in order of least expensive to most expensive. You have to get all three right in order to win.
The only problem is you have your spouse do all the shopping, so you only know that the first prize is between 500 and 2000, the second prize is between 1000 and 2500, and the third prize is between 1500 and 3000.
Which order should you put them in so that you have the highest probability of winning, and what is the probability that you will win using this arrangement?
(In reply to
The Price Is Right by Dan)
The problem is that not all the ways shown are equally likely. For example, the line
15002000 15001999 20002499 123 or 213
should be in total as likely as say
15002000 10001499 25003000 213
and as
15002000 15001999 15001999 any order
so in the case of the splits between two orders, each is entitled to only half a "way", and in the case of "any order" each of those is entitled to only 1/6 of a way. Alternatively multiply each of the individual lines as counting as 6 ways, each possible order in double lines as 3 ways and each of the 6 sharers in "any order" as 1 way.

Posted by Charlie
on 20031016 08:52:08 