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6 teams (Posted on 2023-03-17) Difficulty: 4 of 5
6 football teams each of different level of play compete in a knockout fashion: the 1st pair chosen at random and in the following rounds the winner is facing another randomly chosen team. Given that a certain team won three games so-far what is the probability of winning the 4th game?

No Solution Yet Submitted by Ady TZIDON    
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re: an ambiguity? | Comment 3 of 11 |
(In reply to an ambiguity? by Steven Lord)

Initially I had the same worry about the ambiguity. I wrote my solution on the assumption that the player's first game was indeed the first game of the whole tournament.


My second thought was Does it matter? Just ignore the first game. But then he'd be playing against a proven winner, of at least one game. That would need to be taken into consideration.

The remaining paragraph was removed, as it was completely wrong.


Edited on March 17, 2023, 10:41 am
  Posted by Charlie on 2023-03-17 10:30:06

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