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e pluribus unum ii (Posted on 2004-01-22) Difficulty: 3 of 5
Below are three groups of three numbers each. Combine the numbers in each group using the standard binary operations (addition, subtraction, multiplication, division, and exponentiation) so that each group yields the same number.
  1. 3, 15, 18
  2. 10, 13, 36
  3. 24, 27, 39

For an example, see the first problem.

See The Solution Submitted by DJ    
Rating: 4.6667 (6 votes)

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Comments: ( Back to comment list | You must be logged in to post comments.)
No Subject Comment 12 of 12 |
18-(15/3) = 13
36-(10+13) = 13
39/(27-24) = 13
  Posted by DrBob on 2004-01-29 16:48:00
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