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Sequence Sum (Posted on 2003-12-08) Difficulty: 2 of 5
In a certain sequence, the next term is found by taking the number before it minus the number two numbers before it.

For example, in the sequence a, b, c, d... c = b-a, d = c-b, and so on.

Starting with 54 and 93, what would be the sum of the first six thousand terms?

See The Solution Submitted by Gamer    
Rating: 2.6000 (5 votes)

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Solution Solution (No computer program used) | Comment 5 of 8 |
The first 6 terms in the series are:
54
93
93-54
93-54-93
93-93-93
93-93-93+54

and then the terms begin to repeat....54, 93, etc..

The sum of the first 6,000 terms is:

1000*(54+93+93-54+93-54-93+93-93-93+93-93-93+54)
= 1000*(0)
= ZERO
  Posted by Penny on 2003-12-08 11:31:45
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