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 Set Me Up (Posted on 2004-02-10)
To demonstrate set union and intersection to her class, Mrs. Putnam asked for three students to each write down a set of numbers.

After they had done so, she looked at their sets and told the class, "the union of these three sets is the first ten counting numbers, but their intersection is empty!"

How many triples (A, B, C) of sets are there such that

A U B U C = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
and
A ∩ B ∩ C = {} ?

 See The Solution Submitted by DJ Rating: 4.3636 (11 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(2): Game, set and match !!!! | Comment 20 of 31 |
(In reply to re: Game, set and match !!!! by SilverKnight)

Maybe I should just ride into the subset.....

(A int B) int C = {}

If C has just 1 number (there are 10 such sets), then any two sets A and B, where A is any subset of the remaining 9 numbers, and B is any subset of all 10 numbers, should do the trick. A set of 9 elements has 2^9 subsets. A set of 10 elements has 2^10 subsets.
(10)*(2^9)*(2^10)=5242880

If C has just 2 numbers (there are 10*9 such sets), then any two sets A and B, where A is any subset of the remaining 8 numbers, and B is any subset of all 10 numbers, will work. A set of 8 elements has 2^8 subsets.
(10*9)*(2^8)*(2^10)=23592960

If C has just 3 numbers (there are 10*9*8 such sets), then any two sets A and B, where A is any subset of the remaining 7 numbers, and B is any subset of all 10 numbers, will work.
(10*9*8)*(2^7)*(2^10)=94371840

But the numbers begin to overwhelm my primitive calculator.........
Edited on February 10, 2004, 12:10 pm
 Posted by Penny on 2004-02-10 12:08:54

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