Difficult Sequence (Posted on 2003-10-18)

	Submitted by Freddy Grants
Rating: 3.6667 (9 votes)
Solution:	(Hide)
the solution is 168. formula is n^2+integers ascending/descending from 20, depending on what n equals. for example. the 1st number equals 1^2+20. the 2nd, 2^2+20+21. 3rd = 3^2=20+19+18. 4th, 4^2+20+21+22+23, 5th= 5^2+20+19+18+17+16.odd bases you descend from 20, even bases you asecend from 20. so for the question mark, you would do 7^2+20+19+18+17+16+15+14=168

	Subject	Author	Date
	Problem Solution	K Sengupta	2007-04-20 14:57:03
	hard one	Billy Bob	2004-03-28 15:00:03
	re(2): An alternate approach - I think I got it	Dan	2003-11-02 14:51:22
	re: An alternate approach - I think I got it	Brian Smith	2003-10-27 10:46:37
	Hint	Freddy Grants	2003-10-25 10:13:03
	Hint:	Gamer	2003-10-24 17:04:37
	hint?	pleasance	2003-10-24 07:28:54
	Another approach	Manguexa	2003-10-23 00:05:55
	Odd/Even..	Paul	2003-10-22 19:40:14
	Strange	Fernando Baibich	2003-10-22 15:07:46
	re(2): An alternate approach	Brian Smith	2003-10-21 13:53:37
	re: An alternate approach	SilverKnight	2003-10-21 13:31:52
	An alternate approach	Brian Smith	2003-10-21 13:22:16
	re: This one was tuff !!	SilverKnight	2003-10-21 11:11:38
	This one was tuff !!	Dan	2003-10-21 10:15:42
	solution? maybe not what he had in mind....	SilverKnight	2003-10-20 15:32:35
	re(2): AARRGG..	Fernando Baibich	2003-10-20 15:28:27
	re: AARRGG..	Brian Smith	2003-10-20 15:21:35
	AARRGG..	Paul	2003-10-20 14:04:23