If you have a truncated cone such that its upper base has a radius of a and the radius of its [larger] lower base is b, and a height h (between bases), how could you figure out its surface area using geometric reasoning?

general equation:

--------------------------------------------------------------------------------

Frustrum (= truncated cone):

Volume = 1/3 (pi)* h *( a^ 2 + b^ 2 + a*b )

Surface Area = Lateral Area + Area of Base 1 + Area of Base 2

LA = (pi)* hs * ( a+b )

hs = SQROOT [ (a-b) ^2 + h^ 2 ]

AB 1 = (pi)*a^2

AB 2 = (pi)*b^2

that replaces my previous entry

ady

--------------------------------------------------------------------------------