There is a small town situated by a barbarian colony. The population in this town is very small, but they live well. Upon seeing the villagers in this town so happy, a group of thirty two barbarians sneak up and position themselves around the city. All the barbarians fired at exactly the same time, and every bullet went over 3 villager's heads before it killed another person, including anyone who may have been shot already. If no villager was at the same place at the time (and all villagers were in the town) when the simultaneous shooting occurred, what is the fewest amount of villagers in the town?
(Note: "Around" means actually around. A line going around the city would work, but one going out of the city would not.)
ok, 12 villagers. 10 in the shape of a pentagon.(5 on the points, 5 in the middle of each side) One in the middle and one off center and higher than center. If the pentagon is point up than that piont is A, lableing clockwise through J. Now the center is K and the off center point is L. Now the sides form ABC, CDE, EFG, GHI, IJA forming 5 lines. Lines aslo form AKF, BKG, CKH, and so on forming 10 lines. the point L lines up to form ALG and CLI forming 2 lines. Total we have 17 lines with 2 barbarians on each end. this totals for 34 barbarians.
What do you think?
Posted by York
on 2004-01-30 10:00:03