(In reply to
Getting desperate..... :O) by Penny)
Mmm, yes, I'd agree with your title if that's your final answer..!
The problem with that method (*beyond* being completely absurd) is that Gamer said only about ten letters could be transformed using this method. I could create some semi-random connection with any number to any letter if we start reaching like that.
So let's see... Only a few letters...
It could be based on the shape of the letters, perhaps. M is made up of 4 strokes (the 4 in 64?), R has 3... but the rest of them don't work...
Position in the alphabet...
M = 13
R = 18
DP = (4 * 16) = 64 (hmmm interesting...) or (4 + 16) = 20
N = 14
There doesn't appear to be anything special about those number that could limit the set to only 10...
Hmmmmm.... Still there are no hooks. And still Gamer thinks it's difficulty three... Must be something we're not seeing, unless that guy's gone completely round the bend.
What exactly is it that's coincedental about the two 3 = R's? The fact that 3 comes up twice (the same letter, whatever it may be in the original message), the fact that R comes up twice (R is used twice in the original message), or that fact that 3 = R both times (the original message and the key word have the same letter in that position both times)? Not that I could see where to go with the answer to that.
Hmmmmmmm
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Posted by Sam
on 2004-02-19 15:27:06 |
re: Getting desperate..... :O)
