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Tricky Triangle (Posted on 2003-12-03) Difficulty: 4 of 5
Replace the letters in the diagram with a different number from 0 to 9, such that the sum of the four numbers on all edges are the same, and the sum of the three numbers on all three corners are the same.
          A
        B   C
      D   E   F
    G   H   I   J

In other words, A+C+F+J = A+B+D+G = G+H+I+J and
A+B+C = D+G+H = F+I+J.

No Solution Yet Submitted by Kelsey    
Rating: 3.2500 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: wording change | Comment 6 of 15 |
(In reply to wording change by Cory Taylor)

As the problem stands, E is useless, for it doesn't appear in any of the sums; its only function is to use up a number.
  Posted by Federico Kereki on 2003-12-03 13:11:19

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