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Self-Descriptor (Posted on 2002-07-10) Difficulty: 3 of 5
Find a number ABCDEFGHIJ such that A is the count of how many 0's are in the number, B is the number of 1's, and so on.

(Taken from http://einstein.et.tudelft.nl/~arlet/puzzles/logic.html)

See The Solution Submitted by levik    
Rating: 3.8750 (8 votes)

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Solution Exactly one solution (continued) | Comment 4 of 14 |
It looks like the last paragraph of my solution was cut off even though it accepted the post, so this is my concluding paragraph:

So the number must be 6BC0001000, with B at least 1 and C no greater than 1. Neither B and C can be 0, since there are already six 0's. So C must be 1, making B a 2, and giving the number 6210001000.

  Posted by Ender on 2002-07-11 04:58:19
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