All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers > Sequences
Flawless Series? (Posted on 2003-11-29) Difficulty: 3 of 5
What are the next three numbers in this sequence? 6, 28, 496, 8128, ... ? Please explain how you determined these three numbers.

See The Solution Submitted by SilverKnight    
Rating: 2.8889 (9 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Explain... | Comment 22 of 67 |
(In reply to Explain... by Tristan)

The definition of a perfect number is that it is a number which is equal to the sum of all the numbers that divide exactly into it, including 1, but excluding itself. Thus 6 is a perfect number because 6 is divisible by 1, 2 and 3, and the total of those numbers is also 6. As mentioned, the fact that it is divisible by itself, 6, does not add to the total.

Likewise 28 is divisible by 1, 2, 4, 7 and 14, which add up to 28.

That's how the definition works.

It turns out that all the even perfect numbers are given by
(2^(p-1))*(2^p-1) where p is a prime and 2^p-1 is also prime (this form is called a Mersenne prime). It is believed, but not proved, that there are no odd perfect numbers, so that this list, via Mersenne primes, will find any perfect number at all (is in 1-to-1 correspondence with the perfect numbers).

The alternative solution that I posted previously, uses the mere formula (2^(p-1))*(2^p-1) considering only p as prime without requiring 2^p-1 to be prime. This results in numbers, such as 2096128, showing up on the alternative sequence while not being perfect.
  Posted by Charlie on 2003-11-30 15:22:37

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information