All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Probability
a game of chance (Posted on 2003-12-31) Difficulty: 3 of 5
I have a game where you start with 13 cards (for example a single suit). Randomly select three cards, from which you discard both the lowest and the highest, while returning the median card to the original set. This process is then repeated with the sucessively smaller set until only a single card remains. What is the probability for each of the 13 cards you started with remaining as the last one in the set?

  Submitted by Cory Taylor    
Rating: 4.2500 (4 votes)
Solution: (Hide)
1,13=0

2,12= 24255/6936930 , 0.35%

3,11= 88200/6936930 , 1.27%

4,10= 247695/6936930 , 3.57%

5,9= 619360/6936930 , 8.93%

6,8= 1360975/6936930 , 19.62%

7= 2255960/6936930 , 32.52%

1,13 = 0 / 28314
2,12 = 99 / 28314
3,11 = 360 / 28314
4,10 = 1011 / 28314
5, 9 = 2528 / 28314
6, 8 = 5555 / 28314
7 = 9208 / 28314

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionTHE ANSWER (no real program used)Penny2004-01-03 18:04:42
yikes!Dan Blume2003-12-31 15:59:50
SolutionsolutionCharlie2003-12-31 15:33:08
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (14)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information