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Quadrilateral fun (Posted on 2004-01-10) Difficulty: 4 of 5
Begin with an arbitrary, convex quadrilateral. Next, draw squares outwardly on the sides of the quadrilateral, and join the centers of opposite squares.

You might find the the two resulting lines are equal in length and intersect at precisely 90 degrees.

Prove (or disprove) the notion, that this is always true.

See The Solution Submitted by SilverKnight    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
A Complex Solution Comment 6 of 6 |
Sorry. Did not know that HTML did not work here
as it does when summitting a problem. It would
have been the same as that linked to by Federico.

Edited on July 24, 2004, 3:05 am
  Posted by Bractals on 2004-07-24 02:50:08

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