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Three Bugs (Posted on 2004-01-22) Difficulty: 4 of 5
Remember this one?

In this problem, the three bugs start at the corners of an equilateral triangle (with side length=10 inches).

Again, the bugs travel directly towards their neighbor (counter-clockwise). And, again, each bug homes in on its target, regardless of its target's motion. So, their paths will be curves spiraling toward the center of the triangle, where they will meet.

What distance will the bugs have covered by then, and how did you determine it?

See The Solution Submitted by SilverKnight    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: There must be some bugs in this solution !!! | Comment 13 of 16 |
(In reply to There must be some bugs in this solution !!! by Penny)

"10/(1-cos[2*pi/N radians])
= 10/(1-cos[120 degrees])
= 20"

Since cos(120 degrees) = -.5, it follows that
1-cos(120 degrees) = 1.5, and
10/1.5 = 6.666666666666...

  Posted by Charlie on 2004-01-23 00:40:34

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