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Game of luck (Posted on 2004-01-27) Difficulty: 2 of 5
4 people play a game of chance. They each take turns until everyone has taken a turn, then they begin a new round. They stay in the same order every round. Every time a player takes a turn, they have a certain chance of winning. When someone wins, the game ends. They all have even odds of winning a game. The chance of someone winning in any given round is 3/5.

What is the probability for each person to win during their turns?

See The Solution Submitted by Tristan    
Rating: 3.4000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: my solution | Comment 11 of 22 |
(In reply to my solution by Ady TZIDON)

Ady, you wrote:
pb=x*( 1-x)
pc=x*( 1-x)*(1-pb)
pd=x*( 1-x)*(1-pb)*(1-pc)
and pa+pb+pc+pd=3/5

this is not the case (well the last line anyway...)

It should read:
(1-pa)(1-pb)(1-pc)(1-pd) = (1 - 3/5)

  Posted by SilverKnight on 2004-01-30 14:08:05

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