All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
trigonometry and a triangle (Posted on 2004-02-26) Difficulty: 4 of 5
Prove that in a triangle ABC,:

sin(A)sin(B)sin(C) + cos(A)cos(B) = 1


A = B = 45 and C = 90.

See The Solution Submitted by mohan    
Rating: 2.7143 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts re: solution | Comment 6 of 14 |
(In reply to solution by jacob)

sin(a)sin(b)sin(c) <= sin(a)sin(b) only if
sin(a)sin(b)>=0. I like the style of the
proof, but this should be fixed.
  Posted by Federico Kereki on 2004-02-27 06:43:35

Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information