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trigonometry and a triangle (Posted on 2004-02-26) Difficulty: 4 of 5
Prove that in a triangle ABC,:

sin(A)sin(B)sin(C) + cos(A)cos(B) = 1

implies:

A = B = 45° and C = 90°.

See The Solution Submitted by mohan    
Rating: 2.7143 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
lol | Comment 8 of 15 |
lol i dont know what this problem is about, but it has probly been used before.  It is hard to think of mew, original problems like that when there are already so many out there.
  Posted by matt runchey on 2004-02-27 17:36:49
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