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Sum of Cubes (Posted on 2004-05-25) Difficulty: 3 of 5
Prove that the sum of consecutive perfect cubes (starting with 1) is always a perfect square.

For example:
1=1
1+8=9
1+8+27=36

  Submitted by Gamer    
Rating: 3.4000 (5 votes)
Solution: (Hide)
The sum of perfect cubes up to x³ appears to be equal to ((x+1)(x/2))², so this will be called S(x). One easy way to prove is using induction.

Proving S(1) is true:
((1+1)(1/2))² = 1² = 1.

Proving S(x)+(x+1)³=S(x+1) is true:

((x+1)(x/2))²+(x+1)³=
((x+1)²/4)(x²)+((x+1)²/4)(4(x+1))=
((x+1)²/4)(x²+4x+4)=
((x+1)²/2²))((x+2)²=
(((x+1)+1)(x+1)/2)²

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionPuzzle Solution: Formal MethodK Sengupta2022-01-06 01:49:28
What Gamer perhaps had in mind.broll2011-10-10 02:38:30
SolutionPuzzle SolutionK Sengupta2008-11-27 13:24:04
SolutionPraneeth2007-08-14 00:55:25
re(2): an arbitrary n solution...ryan2005-09-20 04:43:38
re: an arbitrary n solution...Dan2005-09-06 08:14:32
an arbitrary n solution...ryan2005-08-14 21:55:39
SolutionsolutionPemmadu Raghu Ramaiah2005-01-09 02:45:14
SolutionNo SubjectPemmadu Raghu Ramaiah2005-01-09 02:31:13
Solutionalgebraic solutionDanny2004-05-25 16:45:17
SolutionDifference MethodRichard2004-05-25 16:06:56
SolutionSolutione.g.2004-05-25 13:10:38
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