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e, i, and π (Posted on 2004-03-02) Difficulty: 2 of 5
i² = -1
e^(i π) = -1

(-e)^(i π) = ?

Simplify to a number without i. Leave e and π in their symbol forms.

See The Solution Submitted by Tristan    
Rating: 2.8571 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Anotehr elegant method... | Comment 10 of 12 |

(-e)^in = (-1)^in * e^in     (n=pi)

=(e^in)^in *-1

=(e)^(i*i*n*n) *-1

=-e^(-n^2)


  Posted by Kenny M on 2006-02-07 21:16:33
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