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Happy Birthday (2) (Posted on 2004-03-11) Difficulty: 5 of 5
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Well, this time, the question is:
Assuming that birthdays are evenly distributed around 365 days of the year...
what is the minimum number of people I must have in a room, such that the odds are that at least n people share the same birthday?

Let's limit this question to n values from 1 to 12.

We know that for n=1, 1 person is sufficient.

For n=2, as is described in Happy Birthday, 23 people are sufficient.

What are the minimum numbers for n=3 to 12?

See The Solution Submitted by SilverKnight    
Rating: 2.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Link | Comment 3 of 6 |
http://mathworld.wolfram.com/BirthdayProblem.html
  Posted by Richard on 2004-03-12 23:05:15
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