Find the definite integral of f(x) between x = 0 and x = 1

Substituting x = sin h, we have:

I = Integral (cos^2 h) dh; h = 0 to  pi/2

= 1/2*B(1/2, 3/2)

 Now, gamma(1/2) = Vpi, and gamma(3/2) = 1/2*gamma(1/2) = vpi/2

 =  {(1/2)(V(pi)*V(pi)/2}/gamma(2)

= (1/2)*(pi/2), since gamma(2)=1!=1

= pi/4

Edited on December 7, 2022, 11:17 pm

Posted by K Sengupta on 2007-08-29 12:28:52