Let f(x) = √(1-x²)

Find the definite integral
of f(x) between x = 0 and x = 1

Substituting x = sin h, we have:

I = Integral (cos^2 h) dh; h = 0 to pi/2

= 1/2*B(1/2, 3/2)

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= 1/2*(V(pi)*V(pi)/2)/| 2

= (1/2)*(pi/2)

= pi/4

*Edited on ***August 29, 2007, 12:36 pm**