All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math > Calculus
Definite Integral (Posted on 2002-08-06) Difficulty: 3 of 5
Let f(x) = √(1-x²)

Find the definite integral of f(x) between x = 0 and x = 1

  Submitted by Cheradenine    
Rating: 3.0000 (8 votes)
Solution: (Hide)
An integral is the area under a curve

f(x) = y = √(1-x²)
squaring..
y² = 1 - x²
x² + y² = 1²

a bell should ring at this point. this is the equation of a circle radius = 1 centered at 0,0. because x² is a 2-to-1 function and the limits are x=0-1, only 1/4 of the area contributes.

A = πr²/4 = π/4.

So the value of the integral is π/4

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Some Thoughtsre: Easy solutionK Sengupta2022-12-07 00:02:26
SolutionSolutionK Sengupta2007-08-29 12:28:52
More GenerallyRichard2006-08-26 13:17:33
Actual integral solutionOsi2004-11-05 09:04:46
piece o' pieParryHotter2004-02-26 10:52:59
re: solution?saad2003-07-17 18:37:24
solution?saad2003-07-17 18:29:05
No Subjectmathemagician2003-07-04 01:43:42
re(6): Easy solutionTomM2002-08-08 21:33:43
re(5): Easy solutionCheradenine2002-08-08 07:15:08
re(4): Easy solutionlevik2002-08-08 03:37:31
re(3): Easy solutionTomM2002-08-07 18:49:40
re(2): Easy solutionJim Lyon2002-08-07 10:48:55
Questionre: Easy solutionlevik2002-08-06 06:43:58
SolutionEasy solutionJim Lyon2002-08-06 06:16:05
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (13)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information