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new operations (Posted on 2004-03-31) Difficulty: 3 of 5
Mathematicians have just created three new operation symbols, @, $,and _, each doing a different thing to a pair of numbers (All of these symbols can be derived from already-known operations and notations). The following equations using the new symbols are correct:

5@5= 2/5
2@2= 1
2@3= 5/9
3@4= 7/16
2@4= 3/8

1$0= undefined
1$4= 1/10
4$1= 1/10
10$10= 1/50
(1@1) $ 1= (√2)/10

2_2= 6
2_3= 9
6_2= 42
3_5= 30
5_6= 90

If the previous equations are correct, compute the following equation.

1 @ (1 $ (1_1))=

See The Solution Submitted by Victor Zapana    
Rating: 3.3000 (10 votes)

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Beginning Thoughts | Comment 2 of 14 |
I found @, but have only random thoughts for the other two:

@:
5 @ 5 = 2/5 = 10/25 = (5+5)/5²
2 @ 2 = 1 = 4/4 = (2+2)/2²
2 @ 3 = 5/9 = (2+3)/3²
3 @ 4 = 7/16 = (3+4)/4²
2 @ 4 = 3/8 = 6/16 = (2+4)/4²

$:
1$0 undefined - presumably division by 0 is involved
1$4 = 1/10 (?) 1+4=5; 1*4=4; 2/(4*5)= 1/10
4$1 = 1/10 (?) 1+4=5; 1*4=4; 2/(4*5)= 1/10
10$10 = 1/50 (?) 10+10=20; 10*10=100; 8/(20*100) = 1/50



_:
2_2 = 6 = 2*3
2_3 = 9 = 3*3
6_2 = 42 = 6*7 or 2*3*7
3_5 = 30 = 2*3*5
5_6 = 90 = 6*3*5 or 2*3*3*5

  Posted by TomM on 2004-03-31 14:36:59
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