All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Special Numbers (Posted on 2004-04-03) Difficulty: 2 of 5
There exists a number oddity with 3 different 4-digit numbers. One is 9801, where (98 + 01)^2 = 9801. It also works with 3025: (30+25)^2 = 3025.
What is the other number?
What is the smallest 6-digit number that would work?
(in other words, in a 6-digit number abcdef: abcdef=(abc+def)^2)

See The Solution Submitted by Victor Zapana    
Rating: 3.6667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
reply to Penny | Comment 6 of 18 |

You are correct, Penny.

In fact if leading zeroes were OK, then 000000 would be a solution, which would be rather silly.   Oh, I neglected to include the possibility that the second 2 or 3 digit number could be zero, so I checked and there are no solutions like that either.

Actually, apologies, since I hadn't read all of Charlie's solution when I first posted, and didn't see his 6 digit solutions.

Edited on April 3, 2004, 7:24 pm
  Posted by Larry on 2004-04-03 19:21:58

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information