Using the digits in 1996 and any operations (but not mathematical constants), try to write equations that have the numbers from 0 to 100 as the answer.

For example with 1995:

0 = 1*(9-9)*5
2 = (19-9)/5

etc.
Provide as many as you can. Digits 1,9,9 and 6 do not have to appear in order. (But each digit **has** to be used - 1 and 6 once, 9 twice.)

*This is more of a game than a puzzle*

(In reply to

Clarification by Dulanjana)

I think you have to use each of the 4 digits once each and you can't miss out any or duplicate any (other than using '9' twice, obviously).

However - can we use a decimal point as an operator?

I've found over half the numbers so far...