Using the digits in 1996 and any operations (but not mathematical constants), try to write equations that have the numbers from 0 to 100 as the answer.

For example with 1995:

0 = 1*(9-9)*5
2 = (19-9)/5

etc.
Provide as many as you can. Digits 1,9,9 and 6 do not have to appear in order. (But each digit **has** to be used - 1 and 6 once, 9 twice.)

*This is more of a game than a puzzle*

(In reply to

Missing numbers by Nick Reed)

Here are some of your missing ones:

(note that |_x_| is used to denote the greatest integer function - very handy in problems like this)

29: 19 + 9 + |_√√6_|

30: 19 + 9 + |_√6_|

32: 1 x 96 / √9

33: 1 + 96 / √9

40: (9 - 1) x (6 - |_√√9_|)

42: (16 - |_ln 9_|) x √9

67: 69 - √9 + 1

71: 69 + √9 - 1

91 x |_9/6_|

Still missing 47, 49, and 89...