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 Zero to a Hundred in 1996 (Posted on 2002-08-15)
Using the digits in 1996 and any operations (but not mathematical constants), try to write equations that have the numbers from 0 to 100 as the answer.

For example with 1995:

• 0 = 1*(9-9)*5
• 2 = (19-9)/5
etc.

Provide as many as you can. Digits 1,9,9 and 6 do not have to appear in order. (But each digit has to be used - 1 and 6 once, 9 twice.)

This is more of a game than a puzzle

•  See The Solution Submitted by levik Rating: 3.4000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(3): Missing numbers | Comment 8 of 27 |
(In reply to re(2): Missing numbers by Nick Reed)

> Ooooo, I don't like that greatest-integer thing. That's cheating... ;-) I'm going to try to make do without needing that...

Cheating? What kind of geek are you? :-P> Everything not explicitly laid out in the rules is fair game.

> I like the 32, 33, 67 and 71 (and implied 31) though - missed those, even though I've used √9 in other places...

D'oh! I missed 31? I really had a hard time waking up this morning...

31: 96 / √9 - 1
47: 9 x (6 - 1) + |_ln 9_|
49: (9 - |_√6_|)^(√9 - 1)
89: 91 - √√16
 Posted by friedlinguini on 2002-08-15 05:38:47

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