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Zero to a Hundred in 1996 (Posted on 2002-08-15) Difficulty: 3 of 5
Using the digits in 1996 and any operations (but not mathematical constants), try to write equations that have the numbers from 0 to 100 as the answer.

For example with 1995:

  • 0 = 1*(9-9)*5
  • 2 = (19-9)/5
    etc.

    Provide as many as you can. Digits 1,9,9 and 6 do not have to appear in order. (But each digit has to be used - 1 and 6 once, 9 twice.)

    This is more of a game than a puzzle

  • See The Solution Submitted by levik    
    Rating: 3.4000 (10 votes)

    Comments: ( Back to comment list | You must be logged in to post comments.)
    Some Thoughts re(4): Missing numbers | Comment 15 of 27 |
    (In reply to re(3): Missing numbers by TomM)

    Well, levik has given us a solution for 41 that doesn't need the idea of floor or ceiling.
    And I just thought of one for 91 on the way home:

    91 = 91+6-((sqrt(9))!)

    So, if we can just find something for 29 we'll have done all 101 without using any exotic operators. Let's go for it - there's only one left after all...
      Posted by Nick Reed on 2002-08-15 11:03:10

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