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e7(20) n2(17) (Posted on 2004-04-13) Difficulty: 5 of 5
s8(9) r6(25) e7(1) e6(13) n6(20) e7(15) r6(25) d7(15)?

See The Solution Submitted by Victor Zapana    
Rating: 3.3000 (10 votes)

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Solution My vision of the solution is now 20-20 | Comment 10 of 31 |

e7(20) n2(17) 

s8(9) r6(25) e7(1) e6(13) n6(20) e7(15) r6(25) d7(15)

20 in base 7 is 26. 17 in base 2 is 10001. 9 in base 8 is 11. 25 in base 6 is 41. 1 in base 7 is 1. 13 in base 6 is 21. 20 is base 6 is 32. 15 in base 7 is 21. 25 in base 6 is 41.

e7(20)=e26   n2(17)=n10001 

s8(9)=s11    r6(25)=r41  e7(1)=e1    e6(13)=e21    n6(20)=n32    e7(15)=e21  

r6(25)=r41     d7(15)=d21  

If we then regard the base numbers as numbers in the decimal system, and then displace the accompanying letter, modulus 26, in a cyclic alphabet (a=1, b=2, ..., z=26):

e26=e   n10001=n17=e 

s11=d    r41=r15=g  e1=f    e21=z    n32=n6=t    e21=z  

r15=g     d21=y   

This results in:

e e

d g f z t z g y

These are two lines in a standard eye chart.

 

 

 

 

 

 

 

 

 

 

 

Edited on April 14, 2004, 9:31 pm
  Posted by Penny on 2004-04-14 21:30:47

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