All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 The Central Cell (Posted on 2004-04-16)
Prove that the central cell (the number in the middle cell) of any 3x3 magic square is always one-third the magic constant (the sum of any side, either 2 major diagonals, or either center row in the magic square).
Show that in any larger square (n x n), the central cell does not need to be 1/n the magic constant.

 See The Solution Submitted by Victor Zapana Rating: 4.5000 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(2): The second part | Comment 9 of 11 |
(In reply to re: The second part by SilverKnight)

From an article at Mathworld the only orders which it is impossible to construct a magic square are 3 and all orders of the form 4k+2.  Included in the article is a method which will generate magic squares for any order of the form 6k+/-1.

http://mathworld.wolfram.com/PanmagicSquare.html

 Posted by Brian Smith on 2004-04-16 19:19:29
Please log in:
 Login: Password: Remember me: Sign up! | Forgot password

 Search: Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information