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 Cars on the road (Posted on 2004-04-09)
If the probability of observing a car (read: at least one car) in 20 minutes on a highway is 609/625, what is the probability of observing a car (read: at least one) in 5 minutes (assuming constant default probability)?

 See The Solution Submitted by SilverKnight Rating: 2.5000 (4 votes)

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 Solution | Comment 3 of 20 |
P(at least one car) = 1 - P(no cars)

So the probability of no cars in 20 minutes = 1 - 609/625 = 16/625

There are four 5-minute intervals in 20 minutes. Assuming they are independent, P(no cars in 20 min.) = P(no cars in 5 minutes)^4
P(no cars in 5 min) = 2/5

The probability of at least one car is then 3/5.

I think the independence assumption is probably not valid in the real world, but the problem seems to indicate we can.

-Jer
 Posted by Jer on 2004-04-09 12:13:22

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