 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Cars on the road (Posted on 2004-04-09) If the probability of observing a car (read: at least one car) in 20 minutes on a highway is 609/625, what is the probability of observing a car (read: at least one) in 5 minutes (assuming constant default probability)?

 See The Solution Submitted by SilverKnight Rating: 2.5000 (4 votes) Comments: ( Back to comment list | You must be logged in to post comments.) Solution To The Problem Comment 20 of 20 | (In reply to puzzle solution by K Sengupta)

Alternatively, let the probability that at least one car was observed in 5 minutes.

Then the probability that one no car was observable in 20 minutes was 1-p, so that the probability that no car would be seen in 20 minutes would correspond to (1-p)^4.

Hence probability of observing at least one car is 1 - (1-p)^4

By the problem:

1 - (1-p)^4 = 609/625
Or, (1-p)^4 = 16/625
Or, 1-p = 2/5
Or, p = 3/5 = 0.6

Thus the required probability is 0.6

 Posted by K Sengupta on 2007-04-17 11:35:26 Please log in:

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