Given a square piece of paper, show how by creasing and folding only, a square of half the area of the original can be obtained.
(In reply to
re(2): Variation: by Charlie)
A couple of clarifications:
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Re:
Call the small creases perpendicular to AB and AD 'X' and 'Y' respectively. AO = AX = AY = .52.
A whole line segment has been labeled X and another Y, but the next equation treats X and Y as points. Actually you want to call the points where the small creases perpendicular to AB and AD meet the edges of the paper X and Y respectively.
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Re:
6. Fold DC up so that D is on AY and C is on BC.
This does not specify how far along AY that D should be placed. It should be placed far enough that the fold itself includes point Y. Likewise for the next fold, which is to include point X.
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I'll leave these corrections rather than edit my original post. I've never tried to explain origami without pictures. Jer>>

Posted by Jer
on 20040408 12:12:14 